0=-16t^2-6t+482

Solution for 0=-16t^2-6t+482 equation:

0=-16t^2-6t+482

We move all terms to the left:

0-(-16t^2-6t+482)=0

We add all the numbers together, and all the variables

-(-16t^2-6t+482)=0

We get rid of parentheses

16t^2+6t-482=0

a = 16; b = 6; c = -482;
Δ = b2-4ac
Δ = 62-4·16·(-482)
Δ = 30884
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{30884}=\sqrt{4*7721}=\sqrt{4}*\sqrt{7721}=2\sqrt{7721}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{7721}}{2*16}=\frac{-6-2\sqrt{7721}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{7721}}{2*16}=\frac{-6+2\sqrt{7721}}{32}
$